In horses, black coats (B) are dominant to chestnut coats (b). Trotting (1) is also dominant to pacing (t). If a homozygous black pacer

(BBtt) is mated to a homozygous chestnut trotter (bbTT), what percent of the offspring will have bbtt?

Question

Ronan Donaldson

Biology

10 April, 03:29

In horses, black coats (B) are dominant to chestnut coats (b). Trotting (1) is also dominant to pacing (t). If a homozygous black pacer

(BBtt) is mated to a homozygous chestnut trotter (bbTT), what percent of the offspring will have bbtt?

+4

Answers (1)

Know the Answer?

Turner Morrow · Answer 1

0%

Explanation:

Both alleles appear homozygous dominant in one of the parents, therefore if you cross them in a punnett square all will be heterozygous.

In horses, black coats (B) are dominant to chestnut coats (b). Trotting (1) is also dominant to pacing (t). If a homozygous black pacer(BBtt) is mated to a homozygous chestnut trotter (bbTT), what percent of the offspring will have bbtt?

In horses, black coats (B) are dominant to chestnut coats (b). Trotting (1) is also dominant to pacing (t). If a homozygous black pacer

(BBtt) is mated to a homozygous chestnut trotter (bbTT), what percent of the offspring will have bbtt?