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27 July, 11:33

In recessive lethal diseases such as tay-sachs disease, carriers have one copy of the normal allele and one copy of the allele for the disease. carriers are represented in the hardy-weinberg formula by

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  1. 27 July, 11:53
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    The hardy weinberg formula is: p2 + 2pq + q2 = 1 Homozygous dominant (healthy) is represented by p2 while homozygous recessive (diseased) is represented by q2. This leaves 2pq as the heterzygous carrier, as it has one p allele and one q allele.
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