What mass of Al contains the same number of atoms as 33.5g of Au

Question

Rebekah Huffman

Chemistry

23 April, 17:16

What mass of Al contains the same number of atoms as 33.5g of Au

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Timothy Gallagher · Answer 1

Stoich questions ...

1) convert the grams of Au to moles

(33.5g) / (196.7g/mol) = ___x___

2) find how many atoms are in that many moles by multiplying it by avogadro's number.

x (moles of Au) * (6.02*10^23) = ?

3) now that you have found the number of atoms of gold, convert it to grams of aluminum by multiplying it by Avogadro's number and multiplying it by the atomic mass of aluminum.

(?) (6.02*10^23) (26.98g/mol) = (mass of Al)