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13 January, 23:05

If a 250.0 mL sealed plastic bag starts out at a temperature of 19.0 °C and after sitting in the sun reaches a temperature of 60.0 °C, what will the new volume of the bag be? Assume the pressure inside the bag remains constant. A. 219 mL B. 267 mL C. 272 mL D. 285 mL

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  1. 13 January, 23:30
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    D

    Explanation:

    If the pressure remains constant then the temperature and Volume are all that you have to consider.

    Givens

    T1 = 19oC = 19 + 273 = 292o K

    T2 = 60oC = 60 + 273 = 333oK

    V1 = 250 mL

    V2 = x

    Formula

    V1/T1 = V2/T2

    250/292 = x/333

    Solution.

    The solves rather neatly. Multiplly both sides by 333

    250*333 / 292 = 333 * x / 333

    Do the multiplication

    250 * 333 / 292 = x

    83250 / 292 = x

    Divide by 292

    x = 285.1 mL

    The answer is D
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