If a 250.0 mL sealed plastic bag starts out at a temperature of 19.0 °C and after sitting in the sun reaches a temperature of 60.0 °C, what will the new volume of the bag be? Assume the pressure inside the bag remains constant. A. 219 mL B. 267 mL C. 272 mL D. 285 mL

Question

Salazar

Chemistry

13 January, 23:05

If a 250.0 mL sealed plastic bag starts out at a temperature of 19.0 °C and after sitting in the sun reaches a temperature of 60.0 °C, what will the new volume of the bag be? Assume the pressure inside the bag remains constant. A. 219 mL B. 267 mL C. 272 mL D. 285 mL

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Answers (1)

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Kailyn Day · Answer 1

D

Explanation:

If the pressure remains constant then the temperature and Volume are all that you have to consider.

Givens

T1 = 19oC = 19 + 273 = 292o K

T2 = 60oC = 60 + 273 = 333oK

V1 = 250 mL

V2 = x

Formula

V1/T1 = V2/T2

250/292 = x/333

Solution.

The solves rather neatly. Multiplly both sides by 333

250*333 / 292 = 333 * x / 333

Do the multiplication

250 * 333 / 292 = x

83250 / 292 = x

Divide by 292

x = 285.1 mL

The answer is D