A gas occupying a volume of 425 mL at a pressure of 2 atm is allowed to expand until the pressure reaches 588 mmHg. What is the final volume in mL?

Answer: 1098.6 mL

Explanation:

Given that,

Initial volume of gas (V1) = 425mL

Initial pressure of gas (P1) = 2 atm

[Since final pressure is given in mmHg, convert 2 atm to mmHg

1 atm = 760 mmHg

2 atm = 2 x 760 = 1520 mmHg]

Final volume of gas (V2) = ?

Final pressure of gas (P2) = 588 mmHg

Since pressure and volume are given while temperature remains the same, apply the formula for Boyle's law

P1V1 = P2V2

1520 mmHg x 425mL = 588 mmHg x V2

646000 mmHg•mL = 588 mmHg•V2

Divide both sides by 588 mmHg

646000 mmHg•mL/588 mmHg = 588 mmHg•V2/588 mmHg

1098.639 mL = V2

Round the 1098.639 to the nearest tenth, hence it becomes 1098.6

Thus, the final volume of the gas is 1098.6 mL