A sample of solid iron is heated with an electrical coil. If 85.7 Joules of energy are added to a 14.3 gram sample initially at 24.7 °C, what is the final temperature of the iron?

The final temperature of the iron is: - 38.0 °C

Explanation:

The initial temperature = 24.7 °C

Let Final temperature = T °C

Using,

Q = m C * ΔT

Where,

Q is the heat absorbed by the iron = 85.7 J

C gas is the specific heat of the iron = 0.45 J/g °C

m is the mass of iron = 14.3 g

ΔT is the change in temperature. (T - 24.7) °C

Applying the values as:

Q = m C * ΔT

85.7 J = 14.3 g * 0.45 J/g °C * (T - 24.7) °C

Solving for T, we get that:-

T = 38.0 °C

The final temperature of the iron is: - 38.0 °C