Ask Question
11 January, 00:51

The chemical equation shows how ammonia reacts with sulfuric acid to produce ammonium sulfate. 2NH3 (aq) + H2SO4 (aq) (NH4) 2SO4 (aq) How many grams of ammonium sulfate can be produced if 60.0 mol of sulfuric acid react with an excess of ammonia

+4
Answers (1)
  1. 11 January, 00:59
    0
    7923.6 g of (NH₄) ₂SO₄ can be produced by this reaction

    Explanation:

    The reaction is:

    2NH₃ (aq) + H₂SO₄ (aq) → (NH₄) ₂SO₄ (aq)

    In this reaction ratio is 1:1.

    As the ammonia is in excess, the limiting reagent is the sulfuric acid.

    So 1 mol of sulfuric can produce 1 mol of sulfate

    Then, 60 moles of sulfuric must produce 60 moles of sulfate.

    We convert the moles to mass:

    60 mol. 132.06 g / 1mol = 7923.6 g
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The chemical equation shows how ammonia reacts with sulfuric acid to produce ammonium sulfate. 2NH3 (aq) + H2SO4 (aq) (NH4) 2SO4 (aq) How ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers