Ask Question
13 October, 08:16

One of the radioactive isotopes used in chemical and medical research is sulfur-35, which has a half-life of 87 days. How long would it take for 0.25 g to remain of a 1.00 g sample of sulfur-35

+5
Answers (1)
  1. 13 October, 08:33
    0
    Time taken = 174 days

    Explanation:

    Half life is the time take for a subsrtance taken to decay to half of it's origial or initial concentration.

    In this probel, the haf life is 87 days, this means that after evry 87 days, the concentration or mass of sulfur-35 decreases by half.

    If the starting mass is 1.00g, then we have;

    1.00g - -> 0.5g (First Half life)

    0.5g - -> 0.25g (Second half life)

    This means that sulphur-335 would undergo two half lives for 0.25g to remain.

    Total time taken = Number of half lives * Half life

    Time taken = 2 * 87

    Time taken = 174 days
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “One of the radioactive isotopes used in chemical and medical research is sulfur-35, which has a half-life of 87 days. How long would it ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers