Assuming all the nh3 dissolves and that the volume of the solution remains at 0.300 l, calculate the ph of the resulting solution.

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Tootsie

Chemistry

18 June, 17:10

Assuming all the nh3 dissolves and that the volume of the solution remains at 0.300 l, calculate the ph of the resulting solution.

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Alex Haas · Answer 1

Assume p=735 Torr V = 7.6L R=62.4 T = 295 PV-nRT (735 Torr) (7.60L) = n (62.4Torr-Litres/mole-K) (295K) 0.30346 moles of NH3 Find moles 0.300L solution of 0.300 M HCL = 0.120 moles of HCL 0.30346 moles of NH3 reacts with 0.120 moles of HCL producing 0.120 moles of NH4 + ION, and leaving 0.18346 mole sof NH3 behind Find molarity 0.120 moles of NH4+/0.300L = 0.400 M NH4 + 0.18346 moles of NH3/0.300L = 0.6115 M NH3 NH4OH - - > NH4 & OH - Kb = [NH4+][OH]/[NH4OH] 1.8 e-5=[0.300][OH-]/[0.6115] [OH-]=1.6e-5 pOH = 4.79 PH=9.21.