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4 November, 10:04

The observed rotation of 2.0 g of a compound in 50 mL of solution in a polarimeter tube 20 cm long is + 138°. What is the specific rotation of the compound?

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  1. 4 November, 10:24
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    +1725

    Explanation:

    The specific rotation can be calculated using the formula:

    Specific Rotation = Observed Rotation / (l * C)

    Where l is the path length in decimeters (20 cm / 10), 2 dm; and C is the concentration of the compound in mg/mL (2.0g / 50mL), 0.04 g/mL.

    Putting the data we're left with:

    Specific Rotation = + 138 / (2 * 0.04) = + 1725
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