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26 August, 22:31

How many L of 0.75 M Ca (OH) 2 (aq) are needed in order to have 5.5 mol of Ca (OH) 2?

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  1. 26 August, 22:51
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    7 1/3 L.

    Explanation:

    1 liter of 0.75 M Ca (OH) 2 aq contains 1 mole of Ca (OH) 2.

    By proportion that would be 5.50 / 0.75 L

    = 7 1/3 L.
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