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19 October, 17:52

Calculate the pH of each of following buffered solutions.? a. 0.10 M acetic acid/0.25 M sodium acetate b. 0.25 M acetic acid/0.10 M sodium acetate c. 0.080 M acetic acid/0.20 M sodium acetate d. 0.20 M acetic acid/0.080 M sodium acetate

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  1. 19 October, 17:56
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    a. 5.10.

    b. 4.35.

    c. 5.10.

    d. 4.35.

    Explanation:

    a. 0.10 M acetic acid/0.25 M sodium acetate

    For acidic buffer:

    ∵ pH = pKa + log [salt]/[Acid]

    ∴ pH = - log (Ka) + log [salt]/[Acid]

    Ka for acetic acid = 1.8 x 10⁻⁵.

    ∴ pH = - log (1.8 x 10⁻⁵) + log (0.25) / (0.10)

    ∴ pH = 4.744 + 0.34 = 5.084 ≅ 5.10.

    b. 0.25 M acetic acid/0.10 M sodium acetate

    For acidic buffer:

    ∵ pH = pKa + log [salt]/[Acid]

    ∴ pH = - log (Ka) + log [salt]/[Acid]

    Ka for acetic acid = 1.8 x 10⁻⁵.

    ∴ pH = - log (1.8 x 10⁻⁵) + log (0.10) / (0.25)

    ∴ pH = 4.744 - 0.34 = 4.346 ≅ 4.35.

    c. 0.080 M acetic acid/0.20 M sodium acetate

    For acidic buffer:

    ∵ pH = pKa + log [salt]/[Acid]

    ∴ pH = - log (Ka) + log [salt]/[Acid]

    Ka for acetic acid = 1.8 x 10⁻⁵.

    ∴ pH = - log (1.8 x 10⁻⁵) + log (0.20) / (0.08)

    ∴ pH = 4.744 + 0.34 = 5.084 ≅ 5.10.

    d. 0.20 M acetic acid/0.080 M sodium acetate

    For acidic buffer:

    ∵ pH = pKa + log [salt]/[Acid]

    ∴ pH = - log (Ka) + log [salt]/[Acid]

    Ka for acetic acid = 1.8 x 10⁻⁵.

    ∴ pH = - log (1.8 x 10⁻⁵) + log (0.08) / (0.20)

    ∴ pH = 4.744 - 0.34 = 4.346 ≅ 4.35.
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