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26 December, 14:54

The titration of 25.0 ml of an unknown concentration h2so4 solution requires 83.6 ml of 0.12 m lioh solution. what is the concentration of the h2so4 solution (in m) ? question 16 options:

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  1. 26 December, 15:23
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    2LiOH + H₂SO₄ = Li₂SO₄ + 2H₂O

    v (H₂SO₄) = 0.025 L

    v (LiOH) = 0.0836 L

    c (LiOH) = 0.12 mol/L

    n (LiOH) = v (LiOH) c (LiOH)

    n (H₂SO₄) = n (LiOH) / 2=v (LiOH) c (LiOH) / 2

    c (H₂SO₄) = n (H₂SO₄) / v (H₂SO₄) = v (LiOH) c (LiOH) / (2v (H₂SO₄))

    c (H₂SO₄) = 0.0836*0.12 / (2*0.025) = 0.20064 mol/L

    ≈0.20 M
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