The titration of 25.0 ml of an unknown concentration h2so4 solution requires 83.6 ml of 0.12 m lioh solution. what is the concentration of the h2so4 solution (in m) ? question 16 options:

2LiOH + H₂SO₄ = Li₂SO₄ + 2H₂O

v (H₂SO₄) = 0.025 L

v (LiOH) = 0.0836 L

c (LiOH) = 0.12 mol/L

n (LiOH) = v (LiOH) c (LiOH)

n (H₂SO₄) = n (LiOH) / 2=v (LiOH) c (LiOH) / 2

c (H₂SO₄) = n (H₂SO₄) / v (H₂SO₄) = v (LiOH) c (LiOH) / (2v (H₂SO₄))

c (H₂SO₄) = 0.0836*0.12 / (2*0.025) = 0.20064 mol/L

≈0.20 M