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30 December, 19:46

How many grams of KO2 are needed to form 8.0 g of O2?

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  1. 30 December, 19:48
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    Using the atomic weights, K = 39, O=16 so KO2 = 39+32=71. So K=39/71 = 0.549 of KO2 and O2=32=0.45KO2 and O2=8g and 0.45KO2=8g so KO2=8/0.45=17.77g. So to check, K=0.549 x 17.77g=9.76 and so K+O2 = 9.76+8g=17.76.
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