2CO (g) + O2 (g) = 2CO2 (g)

Caculate the number of moles of CO2 produced in 6.76 moles of CO are reacted with excess oxygen.

Question

Charity Henderson

Chemistry

16 December, 07:10

2CO (g) + O2 (g) = 2CO2 (g)

Caculate the number of moles of CO2 produced in 6.76 moles of CO are reacted with excess oxygen.

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Answers (1)

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Katherine Clarke · Answer 1

6.76 moles.

Explanation:

2CO (g) + O2 (g) = 2CO2 (g)

When 2 CO mols were reacted with excess O2 then 2 mols of CO2 is created.

Therefore if 6.76 moles reacted, same number of CO2 will be created.

2CO (g) + O2 (g) = 2CO2 (g)Caculate the number of moles of CO2 produced in 6.76 moles of CO are reacted with excess oxygen.

2CO (g) + O2 (g) = 2CO2 (g)

Caculate the number of moles of CO2 produced in 6.76 moles of CO are reacted with excess oxygen.