Select the set of quantum numbers that represents each electron in a ground‑state be atom.

n = 1, l = 0, ml = - 1, ms = 1/2

n = 2, l = 0, ml = 0, ms = - 1

n = 1, l = 0, ml = 0, ms = 1/2

n = 1, l = 0, ml = 0, ms = - 1/2

n = 2, l = 0, ml = 0, ms = 1/2

n = 2, l = 1, ml = 0, ms = - 1/2

n = 2, l = 1, ml = 1, ms = 1/2

n = 2, l = 0, ml = 0, ms = - 1/2

Question

Tristen

Chemistry

29 September, 17:56

Select the set of quantum numbers that represents each electron in a ground‑state be atom.

n = 1, l = 0, ml = - 1, ms = 1/2

n = 2, l = 0, ml = 0, ms = - 1

n = 1, l = 0, ml = 0, ms = 1/2

n = 1, l = 0, ml = 0, ms = - 1/2

n = 2, l = 0, ml = 0, ms = 1/2

n = 2, l = 1, ml = 0, ms = - 1/2

n = 2, l = 1, ml = 1, ms = 1/2

n = 2, l = 0, ml = 0, ms = - 1/2

+5

Answers (1)

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Noel · Answer 1

There are four electronsin a beryllium atom. The four set of quantum numbers for the ground-state beryllium atom are:

n = 1, ℓ = 0, mℓ = 0, ms = + 1/2 n = 1, ℓ = 0, and mℓ =, ms = - 1/2 n = 2, ℓ = 0, mℓ = 0, ms = + 1/2 n = 2, ℓ = 0, and mℓ =, ms = - 1/2

Explanation:

Be is the chemical symbol for beryllium.

The atomic number of beryllium is 4.

Hence, beryllium atoms have 4 protons and 4 electrons.

The electron configuration for the ground-state Be atom, is:

1s² 2s²

So, you have to find the sets of quantum numbers for the two 1s and the two 2 s electrons.

For the two 1s electrons:

Principal quantun number, n.

The principal quantum number, n, is the main energy level and is indicated by the number in front of the letter (kind of orbital).

So, for the two 1s electrons, n = 1

Orbital Angular Momentum Quantum Number, ℓ

The angular moment quantum number, ℓ, is the shape of the orbital.

The possible numbers for ℓ are from 0 to n - 1. Orbital s means ℓ = 0.

Magnetic Quantum Number, mℓ

The magnetic quantum number, mℓ, represents the space orientation of the orbital.

The possible numbers for mℓ are from - ℓ to + ℓ. Hence, for the two 's electrons mℓ is 0.

So far you have: n = 1, ℓ = 0, and mℓ = 0.

Spin quantum number, s or ms

The spin quantum number, related to the rotation of the electron, may be only + 1/2 or - 1/2.

So, now you have the two sets for these two electrons:

n = 1, ℓ = 0, mℓ = 0, ms = + 1/2 n = 1, ℓ = 0, and mℓ =, ms = - 1/2

For the two 2s electrons:

n = 2

ℓ = 0 (because the orbital is 2)

mℓ = 0 (because ℓ = 0)

ms = + 1/2 or - 1/2.

So, the two sets for the two s electrons are:

n = 2, ℓ = 0, mℓ = 0, ms = + 1/2 n = 2, ℓ = 0, and mℓ =, ms = - 1/2