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18 March, 08:48

Calculate the ph of a solution that has a [oh-] = 2.50 x 10-4m.

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  1. 18 March, 08:53
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    It is so simple when you have [OH-] so you will use it to get POH from this formula:

    POH = - ㏒[OH]

    = - ㏒ 2.5 x 10^-4

    = 3.6

    when PH + POH = 14

    ∴ PH = 14 - POH

    = 14 - 3.6 = 10.4
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