Question 1 how much water would you add to 175 ml of 6.00 m hydrochloric acid to prepare a 2.00 m solution of this acid? 350 ml 700. ml 58.3 ml 525 ml none of the above

We can use the following dilution equation

c1v1 = c2v2

where c1 is concentration and v1 is the volume of the concentrated solution

c2 is concentration and v2 is final volume of the diluted solution

substituting the values

6.00 M x 175 mL = 2.00 M x V

V = 525 mL

final volume of the diluted solution is 525 mL

since there's already 175 mL of acid,

volume of water to be added - 525 - 175 = 350 mL

350 mL of water should be added