The specific heat of copper is 0.385 j / (g · °c). if 34.2 g of copper, initially at 24.0°c, absorbs 4.689 kj, what will be the final temperature of the copper?

We know the relation between heat and temperature follows the formula: Q = Ce * m * (Tf-Ti), where Q is heat transfer, Ce is specific heat, m is mass, Tf is final temperature and Ti is initial temperature. Note that heat value is given in kj so we need to change to joules, then as heat is absorbed the final temperature will increase. 4,689 = 0.385 * 34.2 * (Tf-24) Tf = 4,689 / (0.385 * 34.2) + 24 = 380.12ÂşC