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14 May, 20:51

What pressure in kPa is exerted by 94.60 g CO2 at 57.00 ℃ in 0.7500 L?

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Answers (2)
  1. 14 May, 20:53
    0
    7859.98 KPa

    Explanation:

    Step 1:

    Data obtained from the question. This includes the following:

    Mass of CO2 = 94.60g

    Temperature (T) = 57℃

    Volume (V) = 0.75 L

    Pressure (P) = ?

    Step 2:

    Determination of the number of mole of CO2.

    Mass of CO2 = 94.60g

    Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

    Number of mole of CO2 = ?

    Number of mole = Mass/Molar Mass

    Number of mole of CO2 = 94.60/44

    Number of mole of CO2 = 2.15 moles

    Step 3:

    Conversion of celsius temperature to Kelvin temperature.

    Temperature (Kelvin) = temperature (celsius) + 273

    Temperature = 57℃ + 273 = 330K

    Step 4:

    Determination of the pressure. This is illustrated below:

    The pressure can be obtained by using the ideal gas equation as shown below:

    PV = nRT

    Temperature (T) = 330K

    Volume (V) = 0.75 L

    Number of mole (n) = 2.15 moles

    Gas constant (R) = 0.082atm. L/Kmol

    Pressure (P) = ?

    PV = nRT

    0.75 x P = 2.15 x 0.082 x 330

    Divide both side by 0.75

    P = (2.15 x 0.082 x 330) / 0.75

    P = 77.572 atm

    Step 5:

    Conversion of the pressure in atm to KPa. This is illustrated below:

    1 atm = 101.325 KPa

    Therefore, 77.572 atm = 77.572x101.325 = 7859.98 KPa
  2. 14 May, 21:14
    0
    The correct answer is 8,026 x 10³ kPa

    Explanation:

    We have gaseous CO₂ at the following conditions:

    mass = 94.60 g

    T = 57.00ºC = 330 K

    V = 0.7500 L

    We can use the ideal gas equation to calculate the pressure (P):

    P x V = n x R x T

    ⇒ P = (n x R x T) / V

    We need n, which is the number of moles of the gas. In order to calculate this, we have to calculate first the molecular weight (MM) of CO₂ as follows:

    MM (CO₂) = Molar mass C + (2 x Molar mass O) = 12 g/mol + (2 x 16 g/mol) = 44 g/mol

    Now, we can calculate the number of moles (n) of CO₂ from the mass and the molecular weight as follows:

    n = Mass/MM = 96.60 g/44 g/mol = 2.19 moles

    Now we have all the data. So, we introduce the data in the previos equation and calculate the pressure P:

    P = (n x R x T) / V = (2.19 mol x 0.082 L. atm/K. mol x 330 K) / 0.7500 L = 79.0152 atm

    Finally, we have to convert the pressure from atm to kPa. For this, we know that 1 atm = 1,01325 x 10⁵ Pa and 1 kPa = 1000 Pa.

    79.0152 atm x 1,01325 x 10⁵ Pa/atm x 1 kPa/1000 Pa = 8,026 x 10³ kPa
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