A fixed amount of oxygen gas is held in a. 500 L tank at a pressure of 4.39 atm. The tank is connected to an empty 1.50 L tank by a tube with a valve. After this valve has been opened and the oxygen is allowed to flow freely between the two tanks at a constant temperature, what is the final pressure in the system?

Question

Roy Torres

Chemistry

4 February, 18:52

A fixed amount of oxygen gas is held in a. 500 L tank at a pressure of 4.39 atm. The tank is connected to an empty 1.50 L tank by a tube with a valve. After this valve has been opened and the oxygen is allowed to flow freely between the two tanks at a constant temperature, what is the final pressure in the system?

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Answers (1)

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Paul Duncan · Answer 1

1.0975 atm.

Explanation:

According to Boyle's Law: " At constant temperature, the volume of a given quantity of a gas varies inversely with its pressure".

P α 1/V.

∴ P₁V₁ = P₂V₂.

P₁ = 4.39 atm, V₁ = 0.5 L.

P₂ = ? atm, V₂ = 2.0 L.

∴ P₂ = P₁V₁/V₂ = (4.39 atm) (0.5 L) / (2.0 L) = 1.0975 atm.