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29 December, 05:10

A student placed 0.0243 g of magnesium in 50 mL of 0.200 molar HCl solution, producing H2 gas according to the following reaction what is the volume of H2 (g) produce at 300 K and 0.800 atm?

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  1. 29 December, 05:13
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    Volume of hydrogen gas = 0.1539dm3

    Explanation:

    Equation of the reaction

    Mg (s) + 2HCl - -> MgCl2 (aq) + H2 (g)

    Molar concentration of HCl = 0.2mol/dm3

    Mass of magnesium = 0.0243g

    Volume of HCl = 0.05dm3

    No of moles of HCl = Volume * molar concentration

    = 0.05 * 0.5

    = 0.01mol

    No of moles of Magnesium = mass/molecular weight

    Molecular weight of Magnesium = 24g/mol

    No of moles of magnesium = 0.0243/24

    = 0.001013mol

    Using stoichiometry,

    Since 1 mole of Magnesium metal reacted with 2 moles of HCl acid

    HCl is the limiting reagent.

    Therefore, 1 mole of hydrogen gas is given off.

    0.005 mole of hydrogen is given off.

    Using ideal gas law, PV = nRT

    Volume = (0.005 * 0.0821 * 300) / 0.8

    = 0.1539dm3
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