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Kenya Garrett
Chemistry
3 March, 14:02
How many grams of F are in 12.56 g of SF6? h.
+2
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1
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Leroy Cunningham
3 March, 14:28
0
9.80 g
Explanation:
The molecular mass of the atoms mentioned in the question is as follows -
S = 32 g / mol
F = 19 g / mol
The molecular mass of the compound, SF₆ = 32 + (6 * 19) = 146 g / mol
The mass of 6 F = 6 * 19 = 114 g / mol.
The percentage of F in the compound =
mass of 6 F / total mass of the compound * 100
Hence,
The percentage of F in the compound = 114 g / mol / 146 g / mol * 100
78.08 %
Hence, from the question,
In 12.56 g of the compound,
The grams of F = 0.7808 * 12.56 = 9.80 g
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