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Nicholas Ramirez
Chemistry
Yesterday, 21:55
The decomposition of 11.0 g of fe2o3 results in
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Katelyn Wall
Yesterday, 21:57
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2Fe2O3=4Fe+3O2
1 mole Fe2O3=56*2+3*16=160g
2*160g Fe2O3 ... 4*56gFe ... 6*16g O
11gFe2O3 ... x g Fe ... y g O
x=11*4*56 / (2*160) = 7.7 g Fe
y=11*6*16 / (2*160) = 3.3g O
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