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5 April, 08:46

This calculation shows that burning ___ grams of methane (takes in/gives off) ___ energy

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Answers (2)
  1. 5 April, 09:12
    0
    The question lacks some details in order to be answered. Nevertheless, let's just give some examples.

    Given that you are to burn 10 kg of methane (CH4) from 0 to 20°C. The specific heat capacity of methane is 4.475 kJ/kg-K.

    H = mCpT

    H = (10kg) (4.475 kJ/kg-K) (20-0)

    H = 895.00 kJ

    Because of the positive value of enthalpy, methane takes in heat.
  2. 5 April, 09:23
    0
    Formula for heat change: Q = mCΔTwhere

    Q = the heat addedm = massC = specific heatΔT = (Tf - To in absolute temperature)

    note: in this case subtracting the final and initial temperature in Kelvin or Celsius will not make a difference)

    We add everything into the formula: ΔT = T (final) - T (original)

    ΔT = 36.65 - 24.85ΔT = 11.8° CSo the change in temperature is 11.8 degrees

    Q = 41.11x 4.319 x 11.8

    Q = 2095.13 heat of combustion of Methane.

    It shows that burning 41.11g of methane gives of 2095.13 Joules of energy
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