What is the molarity of a HCl solution that contains 13.3 g of HCl in 447 mL of solution? Answer in units of M

0.81M

Explanation:

Molarity, M = number of moles, n / Volume, V

number of moles of HCl, n=

mass of HCl / molar mass of HCl

Mass of HCl = 13.3g

Molar mass of HCl = 1 + 35.5 = 36.5g/mol

n = 13.3/36.5=0.364mol

V = 447mL=447/1000 L = 0.447L

Note that M is mol/L, hence, we convert 447mL to L. 1 mL = 1/1000 L

M=0.364mol/0.447L

M = 0.81M

Therefore, the molarity of the HCl solution is 0.81M

0.82M

Explanation:

Molar mass of HCL = 36.46g/mol

No of mole = mass/molar mass

No of mole = 13.3/36.46 = 0.365mol

Conc. = n/V = 0.365/0.447 = 0.82M