2 NH3 + 2 O2 → N2O + 3 H2O If 80.0 grams of O2 are reacted in the above reaction, how many grams of N2O will be produced (MM O2=32 g/mol; NH3=17.04 g. mol, N2O=44.02 g/mol, H2O=18.02 g/mol) ?

29.1 g

67.6 g

55.0 g

165 g

2 NH3 + 2 O2 → N2O + 3 H2O

mass of O2 = 80.0g

moles of O2 = 80.0/32 = 2.5 moles O2

moles of N2O = 2.5 moles O2 x 1 mole N2O = 1.25 moles N2O

2 moles of O2

mass of N2O produced;

moles = mass/Molar mass

mass = moles x Molar mass

= 1.25 x 44.02

= 55.025 g N2O

55.025g of N2O is produced in this reaction.