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15 June, 20:06

A common cooking vinegar is 5.0% acetic acid (ch3cooh. how many molecules of acetic acid are present in 41.9 g vinegar?

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  1. 15 June, 20:14
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    To calculate the number of molecules ch3cooh in a given amount of vinegar, we first need to determine the amount of ch3cooh in the solution by multiplying the percent ch3cooh with the sample amount. Then, convert g to moles and use avogadro's number. We do as follows:

    41.9 g vinegar solution (.05 g ch3cooh / g vinegar solution) (1 mol / 60.05 g) (6.022x10^23 g / 1 mol) = 2.1x10^22 molecules ch3cooh
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