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1 August, 15:59

A 50 gram object with a specific heat of 0.3825 J/g*C releases 4593 joules of heat.

If the initial temperature was 235.16C, calculate the final temperature.

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  1. 1 August, 16:07
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    475.26°C

    Explanation:

    Given parameters:

    Mass of object = 50g

    Specific heat = 0.3825J/g°C

    Quantity of heat = 4593Joules

    Initial temperature = 235.16°C

    Unknown:

    Final temperature = ?

    Solution:

    The quantity of heat absorbed by a body is a function of the mass, specific heat capacity and temperature change the body undergoes.

    Mathematically, this relationship is given as;

    H = m c Ф

    where H is the quantity of heat

    m is the mass of the body

    c is the specific heat capacity

    Ф is the temperature difference

    Ф = final temperature - initial temperature

    Since we are solving for final temperature, let us substitute for other given parameters;

    H = m c (final temperature - initial temperature)

    4593 = 50 x 0.3825 x (F - 235.16)

    F - 235.16 = 240.1

    F = 240.1 + 235.16 = 475.26°C
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