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15 July, 05:16

How many liters of hydrogen gas at stp are produced from the reaction of 50.0g of magnesium and 75g of hydrochloric acid

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  1. 15 July, 05:18
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    Here's how to do it:

    Balanced equation first:

    Mg + HCl = H2 + MgCl2 unbalanced

    Mg + 2 HCl = H2 = MgCl balanced

    Therefore 1 mole Mg reacts with 2 moles Hcl.

    50g Mg = ? moles (a bit over 2; you work it out)

    75 g HCl = ? moles (also a bit over 2; you work it out)

    BUT, you need twice the moles HCl; therefore it is the Mg that is in excess. (you can now work out how many moles are in excess, and therefore how much mg is left over).

    So, 2 moles HCl produce 1 mole H2 (g)

    therefore, the amount of H2 produced is half the number of moles of HCl

    At STP, there are X litres per mole of gas (look it up - about 22 from memory)

    Therefore, knowing the moles of H2, you can calculate the volume
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