How many milliliters of ozone gas at at 25.0°C and 1.00 atm pressure are needed to react with 45.00 mL of a 0. 300 M aqueous solution of KI according to the chemical equation shown below? O3 (g) + 2 I - (aq) + H2O (l) → O2 (g) + I2 (s) + 2 OH - (aq)

Question

Remington Marshall

Chemistry

29 September, 16:23

How many milliliters of ozone gas at at 25.0°C and 1.00 atm pressure are needed to react with 45.00 mL of a 0. 300 M aqueous solution of KI according to the chemical equation shown below? O3 (g) + 2 I - (aq) + H2O (l) → O2 (g) + I2 (s) + 2 OH - (aq)

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Peep · Answer 1

Step 1) get the moles of any substance with information provided (KI)

0.045L*0.100mols/L = 0.0045mol of KI which is equal to mols of I - as KI - > (K+) + (I-)

Step 2) get the moles of substance needed (03) use the formula

0.0045mols I - * (1mol of O3) / (2 mols I-) = 0.00225 mols O3