A mixture of n2 (g) and h2 (g) reacts in a closed container to form ammonia, nh3 (g). the reaction ceases before either reactant has been totally consumed. at this stage 1.0 mol n2, 1.0 mol h2, and 1.0 mol nh3 are present. part a how many moles of n2 and h2 were present originally?

Question

Imani Foster

Chemistry

22 October, 20:05

A mixture of n2 (g) and h2 (g) reacts in a closed container to form ammonia, nh3 (g). the reaction ceases before either reactant has been totally consumed. at this stage 1.0 mol n2, 1.0 mol h2, and 1.0 mol nh3 are present. part a how many moles of n2 and h2 were present originally?

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Taryn · Answer 1

The balanced chemical equation:

N2 + 3H2 → 2NH3

We see that 1mol N2 reacts with 3mol H2 to produce 2mol NH3

But we produced 1.0mol NH3

We rewrite the word equation to reflect this change by dividing all numbers by 2.

0.5Mol N2 reacts with 1.5mol H2 to produce 1.0mol NH3

Original amounts:

N2 = 1.0+0.5 = 1.5 mol N2 originally

H2 = 1.0 + 1.5 = 2.5 mol H2 originally.