Here is the balanced chemical equation for the combustion of isopropyl alcohol: 2C3H7OH (l) + 9O2 (g) → 6CO2 (g) + 8H2O (g) Multiplying 42 by 2/3, or 0.667, would be most useful for which calculation?

A. Calculating the moles of O2 needed to produce 42 moles of CO2.

B. Calculating the moles of CO2 that will form from 42 moles of C3H7OH.

C. Calculating the moles of O2 that will react completely with 42 moles of C3H7OH.

D. Calculating the moles of CO2 that will form from 42 moles of O2.

Question

Jazlyn Frey

Chemistry

3 July, 04:59

Here is the balanced chemical equation for the combustion of isopropyl alcohol: 2C3H7OH (l) + 9O2 (g) → 6CO2 (g) + 8H2O (g) Multiplying 42 by 2/3, or 0.667, would be most useful for which calculation?

A. Calculating the moles of O2 needed to produce 42 moles of CO2.

B. Calculating the moles of CO2 that will form from 42 moles of C3H7OH.

C. Calculating the moles of O2 that will react completely with 42 moles of C3H7OH.

D. Calculating the moles of CO2 that will form from 42 moles of O2.

+5

Answers (2)

Know the Answer?

Anton Gaines · Answer 1

Hello there.

Here is the balanced chemical equation for the combustion of isopropyl alcohol: 2C3H7OH (l) + 9O2 (g) → 6CO2 (g) + 8H2O (g) Multiplying 42 by 2/3, or 0.667, would be most useful for which calculation?

A. Calculating the moles of O2 needed to produce 42 moles of CO2.

Cayden Schroeder · Answer 2

I believe the correct answer from the choices listed above is option A. Multiplying 42 by 2/3, or 0.667, would be most useful for c alculating the moles of O2 needed to produce 42 moles of CO2. Hope this answers the question.