If the reaction to form water were written h2 (g) + 12o2 (g) →h2o (g), would you expect the same value of δh as in equation 2h2 (g) + o2 (g) ⟶2h2o (g) δh=-483.6kj?

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Chemistry

30 October, 16:25

If the reaction to form water were written h2 (g) + 12o2 (g) →h2o (g), would you expect the same value of δh as in equation 2h2 (g) + o2 (g) ⟶2h2o (g) δh=-483.6kj?

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Triston Davidson · Answer 1

The answer to this question would be: false

In this question, there is two similar equation but the second equation have twice coefficient than the first equation. The enthalpy of the first equation should be half of the second equation since the amount of molecule react in the equation is also half as much. The enthalpy of first equation should be: - 241.8 kJ