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17 March, 15:18

What is the density (in g/l) of a gas with a molar mass of 146.06 g/mol at 1.03 atmosphere and 297 k

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  1. 17 March, 15:33
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    According to Ideal Gas Equation,

    P V = n R T

    Also,

    n = mass / M. mass

    So,

    P V = (mass * R * T) : M. mass

    Or,

    P * M. mass = (mass * R * T) : V

    Since,

    Density = mass / volume

    So,

    P * M. mass = Density * R * T

    Or,

    Density = (P * M. mass) : (R * T)

    Putting Values,

    Density = (1.03 atm * 146.06 g/mol) : (0.0821 L. atm. mole⁻¹. K⁻¹ * 297 K)

    Density = 6.16 g/L
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