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12 June, 17:14

At 50.14k a substance has a vapor pressure of 258.9 torr. calculate its heat of vaporization in kj/mol if it has a vapor pressure of 277.5 torr at 161.2k

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  1. 12 June, 17:33
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    T₁ = 50,14 K.

    p₁ = 258,9 torr.

    T₂ = 161,2 K.

    p₂ = 277,5 torr.

    R = 8,314 J/K·mol.

    Using Clausius-Clapeyron equation:

    ln (p₁/p₂) = - ΔHvap/R · (1/T₁ - 1/T₂).

    ln (258,9 torr/277,5 torr) = - ΔHvap/8,314 J/K·mol · (1/50,14 K - 1/161,2 K).

    -0,069 = - ΔHvap/8,314 J/K·mol · (0,0199 1/K - 0,0062 1/K).

    0,0137·ΔHvap = 0,573 J/mol.

    ΔHvap = 41,82 J.
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