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18 April, 03:40

a gas has a volume of 14.5 L at 22.9 Celsius and 3.4 atm. what will the new volume be at 44.5 Celsius and 778 torr?

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  1. 18 April, 04:01
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    51.8 L is the new volume

    Explanation:

    In the two situations we have this relationship:

    P ₁. V₁ / T₁ = P₂. V₂ / T₂

    Let's convert the temperature to absolute values

    T°K = T°C + 273

    22.9°C + 273 = 295.9 K

    44.5°C + 273 = 317.5 K

    Let's convert now, the Torr to atm.

    778 Torr. 1 atm / 760 Torr = 1.02 atm

    Now we can replace:

    3.4 atm. 14.5L / 295.9K = 1.02 atm. V₂ / 317K

    (3.4 atm. 14.5L / 295.9K). 317 K = 1.02 atm. V₂

    ((3.4 atm. 14.5L / 295.9K). 317 K) / 1.02 atm = V₂ → 51.8 L

    P ₁. V₁ / T₁ = P₂. V₂ / T₂ is derived from the Ideal Gases Law equation, and it is fulfilled when the moles of a gas, remains constant after the change of T°, pressure and volume.
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