Determine the number of moles of N atoms in 46.5g of Mg (NO3) 2

Question

Elaina Richard

Chemistry

12 December, 21:17

Determine the number of moles of N atoms in 46.5g of Mg (NO3) 2

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Cornelius · Answer 1

First, we determine the moles of Mg (NO₃) ₂ present:

moles = mass / Mr

= 46.5 / (24 + 2 x (14 + 16 x 3))

= 0.4 mole

Each mole of Mg (NO₃) ₂ contains 2 moles of Nitrogen atoms.

Moles Nitrogen = 0.4 x 2

= 0.8 mole