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26 April, 05:28

What is the empirical formula of a compound that contains 40 percent carbon, 6.7 percent hydrogen, and 53.3 percent oxygen by mass?

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  1. 26 April, 05:39
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    40.0 g C * 1 mol C / 12.0 g C = 3.333 mol C

    6.7 g H * 1 mol H / 1.008 g H = 6.6 mol H

    53.3 g O * 1 mol / 16.0 g O = 3.331 mol O

    divide by the least moles

    3.333 mol C / 3.331 = 1

    6.6 mol H / 3.331 = 1.98 ~ 2

    3.331 mol O / 3.331 = 1

    empirical formula is H2CO
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