The oxidation numbers of nitrogen in NH3, HNO3, and NO2 are, respectively: - 3, - 5, + 4 + 3, + 5, + 4 - 3, + 5, - 4 - 3, + 5, + 4

Question

Maxim Burton

Chemistry

8 June, 13:03

The oxidation numbers of nitrogen in NH3, HNO3, and NO2 are, respectively: - 3, - 5, + 4 + 3, + 5, + 4 - 3, + 5, - 4 - 3, + 5, + 4

+4

Answers (1)

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Mohammed James · Answer 1

In NH3, let oxidation number of N be x

x + (+1) 3 = 0

x = - 3

In HNO3, let oxidation number of N be x

1 + x + (-2) 3 = 0

x = + 5

In NO2, let oxidation number of N be x

x + (-2) 2 = 0

x = + 4