Given STP conditions, how many milliliters of hydrogen gas are produced by the reaction 0.020 mol of magnesium with excess of hydrochloric acid?

Question

Danielle Valentine

Chemistry

31 March, 08:48

Given STP conditions, how many milliliters of hydrogen gas are produced by the reaction 0.020 mol of magnesium with excess of hydrochloric acid?

+3

Answers (1)

Know the Answer?

Chanel Rodgers · Answer 1

The balanced equation for the reaction of magnesium and hydrochloric acid is,

Mg + 2HCl - - - > H2 + MgCl2

From the reaction, every 0.02 moles of magnesium will produce 0.02 moles H2. Using the ideal gas equation,

V = nRT / P

Substituting the known values,

V = (0.02 mol) (0.0821 L. atm / mol K) (273 K) / 1 atm

= 0.45 L = 450 mL

Therefore, the hydrogen gas produced is approximately 450 mL.