Ask Question
27 August, 14:28

You are mixing x ml of wine, which is 0.0030 m in sugar, with 20.0 ml of wine, which is 0.00010 m in sugar. the resulting wine is mixed with 30.0 ml of wine, which is 0.0020 m in sugar. the resulting wine is 0.0015 m in sugar. what is the value of x? assume that the volumes are additive.

+3
Answers (1)
  1. 27 August, 14:44
    0
    The rule that we will use to solve this problem is:

    M1V1 + M2V2 + M3V3 = MtVt

    where:

    M1 is the molarity of first solution = 0.003 molar

    V1 is the volume of the first solution which is the X that we want to find

    M2 is the molarity of second solution = 0.0001 molar

    V2 is the volume of second solution = 20 ml

    M3 is the molarity of third solution = 0.002 molar

    V3 is the volume of the third solution = 30 ml

    Mt is the final total molarity = 0.0015 molar

    Vt is the final volume = V1+V2+V3 = X+20+30 = (X+50) ml

    Substitute with the above givens in the equation to get X as follows:

    0.003X + 0.0001 (20) + 0.002 (30) = (X+50) (0.0015)

    0.003X + 0.062 = 0.0015X + 0.075

    0.003X - 0.0015X = 0.075 - 0.062

    0.0015X = 0.013

    X = 0.013 / 0.0015

    X = 8.667 ml
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “You are mixing x ml of wine, which is 0.0030 m in sugar, with 20.0 ml of wine, which is 0.00010 m in sugar. the resulting wine is mixed ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers