How much heat is needed to increase the temperature of a 38g sample of lead from 38 C to 52 c?

121.6J

Explanation:

Given parameters:

Mass of lead = 38g

Initial temperature = 38°C

Final temperature = 52°C

Unknown:

Amount of heat required = ?

Solution:

The amount of heat absorbed by a substance to cause a temperature change is dependent on the mass and specific heat capacity of the body. Specific heat capacity is the amount of heat needed to cause a unit temperature rise of a mass of a substance.

mathematically, heat gained;

H = m C Ф

m is the mass of the lead

Ф is the temperature change

C is the specific heat capacity

Specific heat capacity of lead is 0.16J/g°C

Insert the parameters;

H = 38 x 0.16 x (52-38) = 121.6J