How many grams of oxalic acid dihydrate H2C2O4 ·2H2O, a diprotic acid, are needed to react with 20.00 mL of 0.4500 M NaOH?

Question

Karen Mcmillan

Chemistry

15 May, 00:56

How many grams of oxalic acid dihydrate H2C2O4 ·2H2O, a diprotic acid, are needed to react with 20.00 mL of 0.4500 M NaOH?

+5

Answers (1)

Know the Answer?

Annabella · Answer 1

With the given components above, the chemical reaction required to solve the problem is H2C2O4*2H2O + 2 NaOH = 4 H2O + Na2C2O 4 where 1 mole of diprotic acid needs 2 moles of NaOH to complete the reaction. In this case, given 0.4500 M NaoH and 0.02 L of it, the moles diprotic acid needed is 0.0045 moles. This is equivalent to 0.351 grams.