Ask Question
3 July, 18:07

in acidic solution, the dichromate ion, Cr2O7^2 - (aq) will oxidize Fe^2 + to Fe^3 + and form Cr^3+. What volume of 0.100M Cr2O7^2 - (aq) is required to oxidize 60.0mL of 0.250 M Fe^2 + (aq) ?

+5
Answers (1)
  1. 3 July, 18:17
    0
    The concentration of Fe²⁺ is given as 0.250 M.

    The volume of Fe²⁺ is given as 60.0 ml.

    The concentration of Cr₂O₇²⁻ is given as 0.100 M.

    The following is the reaction:

    Cr₂O₇²⁻ (aq) + 6Fe²⁺ (aq) + 14H⁺ (aq) → 2Cr³⁺ (aq) + 6Fe³⁺ (aq) + 7H₂O (l)

    1 mole of Cr₂O₇ reacts with 6 moles of Fe²⁺

    The moles of Fe²⁺ present in the solution is:

    Moles = Molarity * Volume

    = 0.250 M * 60 ml * 1L / 1000 ml

    = 0.015 ml

    Thus, Fe²⁺ is producing 0.015 mol in the given reaction.

    The volume of Cr₂O₇²⁻ required is:

    1 mole of Cr₂O₇²⁻ = 6 moles of Fe²⁺

    Molarity of Cr₂O₇²⁻ * volume of Cr₂O₇²⁻ - = 1/6 moles of Fe²⁺ present in the reaction

    Volume of Cr₂O₇²⁻ = 0.015 mol/0.600 mol/L

    = 0.025L * 1000ml / 1L

    = 25 ml

    Hence, the volume of Cr₂O₇²⁻ needed is 25 ml.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “in acidic solution, the dichromate ion, Cr2O7^2 - (aq) will oxidize Fe^2 + to Fe^3 + and form Cr^3+. What volume of 0.100M Cr2O7^2 - (aq) ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers