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22 March, 13:33

What volume will o. 128 g of propane, c3h8 occupy at a pressure golf 485 mm Hg and a temperature of 30.0 c

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  1. 22 March, 13:47
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    113 mL

    Explanation:

    Let's apply the Ideal Gases Law for this propose:

    P. V = n. R. T → (n. R. T) / P = V

    We need to convert the T° to Absolute T° and pressure from mmHg to atm

    T° K = 30°C + 273 = 303K

    485 mmHg. 1atm / 760 mmHg = 0.638 atm

    Let's replace the information obtained:

    V = (n. 0.082. 303K) / 0.638 atm

    n = number of moles → 0.128 g. 1mol / 44g = 0.00291 moles

    V = (0.00291 moles. 0.082. 303K) / 0.638 atm → 0.113 L

    The value can be written as 113 mL
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