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29 March, 07:14

During a titration, 40.0 ml of 0.25M NaOH were required to neutralize 50.0ml of HCl. What's the concentration of the HCl solution? Question 6 options: A) 0.40M B) 0.10M C) 0.20M D) 0.25M

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  1. 29 March, 07:38
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    C)

    Explanation:

    M1V1 = M2V2

    40.0ml*0.25M = M2*50.0ml

    M2 = 40.0*0.25/50.0 = 0.20 M
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