1. Calculate the heat change associated with cooling a 350.0 g aluminum bar from

70.0 degrees C to 25.0 degrees C. The specific heat capacity of aluminum is 0.9.

14175 j heat released.

Explanation:

Given dа ta:

Mass of aluminium = 350.0 g

Initial temperature = 70.0°C

Final temperature = 25.0°C

Specific heat capacity of Aluminium = 0.9 j/g.°C

Heat changed = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Heat change:

ΔT = Final temperature - initial temperature

ΔT = 25.0°C - 70°C

ΔT = - 45°C

Q = m. c. ΔT

Q = 350 g * 0.9 j/g.°C * - 45°C

Q = - 14175 j