When 28 g of nitrogen and 6 g of hydrogen react, 34 g of ammonia are produced. if 100 g of nitrogen react with 6 g of hydrogen, how much ammonia will be produced?

N2 + 3H2 - - > 2NH3

When 100g of N2, no of moles of N2 = 100 / (28) = 3.57 mol

no. of moles of h2 = 6 / (2) = 3mol

Therefore h2 is limiting reagent.

no. of moles of ammonia = 3/3*2=2moles

mass of ammonia produced = 2 mol * (14+3) = 34g