Ask Question
18 April, 10:37

10.222 g sample of hydrated barium iodide (Bal) is heated to dry off the water of

crystallization. The dry sample has a mass of 9.520 g. What is the formula of the

hydrate

+2
Answers (1)
  1. 18 April, 11:02
    0
    BaI₂.5H₂O

    Explanation:

    Given dа ta:

    Mass of Hydrated BaI₂ = 10.222 g

    Mass of dried BaI₂ = 9.520 g

    Mass of Water removed = 10.222-9.520 = 0.702 g

    M. Mass of BaI₂ = 391.136 g/mol

    M. Mass of Water = 18.02 g/mol

    Now,

    Calculate moles of dried BaI₂ as,

    Moles = Mass / M. Mass

    Moles = 9.520 g / 391.136 g/mol

    Moles = 0.02434 moles

    Calculate moles of Water as,

    Moles = Mass / M. Mass

    Moles = 0.702 g / 18.02 g/mol

    Moles = 0.0389 moles

    Then,

    Calculate Mole ratio of BaI₂ and water as,

    = 0.02434 moles BaI₂ / 0.0389 moles Water

    = 0.625

    Now,

    We will convert this mole ratio to a whole number by multiplying it with a nearest integer,

    = 0.625 * 8

    = 5

    Hence, this means for every one mole of BaI there are 5 moles of Water.

    Result:

    BaI₂.5H₂O
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “10.222 g sample of hydrated barium iodide (Bal) is heated to dry off the water of crystallization. The dry sample has a mass of 9.520 g. ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers